Question

Two point charges q and -2 q are separated by distance of d in the air find the location of the point relative to q at which the electric potential due to this system is zero

Answer 1

This will help you mate..
Good Luck

Answer 2

Answer:

The required point is at a distance $\frac{d}{3}$ from the charge $\mathrm{q} .$

Explanation:

Let $P$ be the required point at a distance $x$ from charge q

$\begin{aligned}\therefore \frac{1}{4 \pi \varepsilon_{0}} \frac{q}{x}+\frac{1}{4 \pi \varepsilon_{0}} \frac{(-2 q)}{(d-x)} &=0 \\\frac{1}{x} &=\frac{2}{d-x} \\x &=\frac{d}{3}\end{aligned}$

$\therefore$The required point is at a distance $\frac{d}{3}$ from the charge $\mathrm{q} .$