two point charges + q and minus 2 q are placed at the vertices B and C of an equilateral triangle of side is obtained and expression for the magnitude and direction of the resultant electron field at a due to these two charges
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b c are two difht of class 12
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Given:
Two point charges + q and minus 2 q are placed at the vertices B and C of an equilateral triangle.
To find:
Resultant field intensity at point A ?
Calculation:
- At point A , angle between field intensity vectors (from charges at point B and C) are at angle 60°.
- Field intensity due to q charge = kq/a².
- Field intensity due to -2q charge = k(2q)/a².
Now, these vectors are at 60° angle.
Hope It Helps.
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