Two-point charges Q1 = 4.5 μC and Q2 = 8.5 μC are initially very far apart. They are then brought together, with a final separation of 3.5 mm. How much work does it take to bring them together?
Answers
Answered by
4
Answer:
98.4 joule
Explanation:
w = kq1q2/r
w = (9×10^9)(4.5×10^-6)(8.5×10^-6)/0.0035
w = 98.4 joule
k = 9×10^9
1mm = 1000 m
Answered by
3
Given:
Value of Charge Q1 = 4.5 μC
Value of Charge Q2 = 8.5 μC
Final separation of the charges = 3.5 mm.
Find: Work done to bring them together
Solution:
Q1 = 4.5 * 10^ -6, Q2 = 8.5 * 10^ -6
Separation of charger be 'r' = 3.5 mm = 3.5 * 10^-3
Work done to bring them together is given by the formula :
W = K Q1 Q2 / r (Where K = 9×10^9 N ⋅ m^2 /C^2)
W = 9×10^9 * 4.5 * 10^ -6 * 8.5 * 10^ -6 / 3.5 * 10^-3
W = 98.35 Joule
The work done to bring the two charges Q1 and Q2 together is 98.35 Joule.
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