Question

Two point charges +q1 and +q2 are placed in air at a distance 2 m apart. One of the charges is
moved towards the other through a distance of 1 m. The work done is​

Answer 1

Explanation:

Hey Mate

as we know that

Change in energy is equal to work done

So, when charges are 2m apart than energy between tham is = kq1q2/2

And when one of charge moved than finial separation between charges is 1m

new energy is equal kq1q2/2

Hence change in energy is kq1q2/2

And work done is equal to

Kq1q2/2

Remember here we discussed about only potential and displace charge infinitely slowly

Hope it helps you

Answer 2

Answer:

first of all

according to columbic force we will find force after that we will multiple force and displacement. 1×2/4=1/2=0.5

so now 0.5×1=0.5jul