two point charges Q1 and Q2 having masses M and 4m are along a vertical line the magnitude of q2 for the particles to be in vertical equilibrium is
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Answer:
Let initial separation between the particles be l and this remains constant during the motion. If relative separation remains constant then relative velocity should be zero; hence relative acceleration of the particles should also be zero.
a
r
=a
1
−a
2
=0
or
m
1
q
1
E−F
e
=
m
2
F
e
−q
2
E
or
m
1
m
2
(q
1
m
2
+q
2
m
1
)E
=F
e
[
m
1
1
+
m
2
1
]
or (q
1
m
2
+q
2
m
1
)E=F
e
(m
1
+m
2
)=
4πε
0
1
l
2
q
1
q
2
(m
1
+m
2
)
After solving we get, l=
2
1
πε
0
E(q
2
m
1
+q
1
m
2
)
q
1
q
2
(m
1
+m
2
)
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