Question

Two point masses A and B having masses in the ratio 4:3 are separated by a distance of 1,. When another point mass C of mass m is placed in between A and B, the force between A and C is 1/3rd of the force between B and C. Then the distance of C from A is-
Please answer correctly!! asap..its urgent

Answer 1

Answer:

let a point mass C is placed at a distance of x m from the point mass A as shown in the figure.

Here, MBMA=34

Force between A and C is FAC=x2GMMA      .....(i)

Force between B and C is FBC=(1−x)2GMMB   ....(ii)

According to given problem FAC=31FBC

∴X2GMAM=31((1−x)2GMBM)      (using(i) and (ii))

x2MA=3(1−x)2MBorMB

Answer 2

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