Question

Two point masses of 4 kg and 2 kg kept at a distance of 1 m in air attract each other by a force F. These two masses are now dipped in kerosene keeping the distance same. What is the force of attraction between the masses in kerosene?​

Answer 1

Answer:

Two-point masses of 4 kg and 2 kg kept at a distance of 1 m in the air attract each other by a force F. If the same arrangement is kept in kerosene, the force of attraction between them is $F=52.8*10^{-11}N$

Explanation:

• The gravitational force is the interaction between two objects with mass

• If two bodies with masses $m_{1}, m_{2}$ are separated by a distance $r$, the force between them is

        $F=G\frac{m_{1} m_{2} }{r^{2} }$

        where $G=6.6*10^{-11} Nm^{2} kg^{-2}$

• It is independent  of the medium

From the question, we have

the point masses are $m_{1} =4kg$  $m_{2} =2kg$

separation between them $r=1m$

⇒

the gravitational force,

$F=\frac{6.6*10^{-11}*4*2 }{1^{2} }$

$F=52.8*10^{-11}N$