Two points charges +16 µC and -9 µC are placed 8 cm apart in air. Determine the distance of the point from-9 uC where the resultant electric field is zero,
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Answer:
The distance from the smaller charge = 24 cm
Explanation:
|q₁| = 9 µC
|q₂| = 16 µC
dist between charges r = 8 cm
dist of null point from -9C charge (smaller charge) is
x = r /{[√(|q₂| /|q₁| ] - 1}
= 8 /[√16/9 -1]
= 8 / [4/3 -1]
= 8 x 3
= 24cm
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