Question

Two
points charges of
+5X 10-19 C and
are reparated by a distance
1 m. Ar which point, On the line joining
them is electric field is zero​

Answer 1

Answer:

$\mathfrak{\huge{\pink{\underline{\underline{AnswEr:-}}}}}$

Let AB be the distance between two charges 5X10-19C and 20X10-19 C.

Let O be a point between A and B

AO = x , OB= 2-x (2 is the total distance)

kq1 / r1 2 = kq2 / r2 2

5X10-19 / x2 = 20X10-19 / (2-x)2

1/x2 = 4/(2-x)2

Taking square root on both the sides,

1/x = 2/2-x

x = 2/3

Therefore, electric field intensity is zero at a distance 2/3m away from the first charge.