Question

Two points charges +q and -q are placed distance d apart. what are the point at which the resultant electric field is parallel to the line joining the two two charges? ​

Answer 1

all the points between (0,0) to (0,d)


______________> Electric field

(0,0) +q --------------------------- -q (0,d)
|-----------------------------|
d

Answer 2

solution:

If You draw the graph of E v/s X [Taking +q and -q cahrge along x axis and distance osf seperation is "d" and taking electric filed at y axis] (the graph is like rectangular Hyperbola)

you will observe that at just a mid point of the distacnce between them,The field is get || to X Axis .

so, Required point is (d/2,0,0)