two pole of heights 15m and 24m stand on a plane ground if the distance between their feet is 12 m find the distance between their tops
15m
25m
14m
36m
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→ Let the two poles AB and CD are stand upright on the ground of 15m and 10m respectively.
→ AB is the distance between the tops of two poles is of 13m.
→ And, DB is the distance between their feet.
▶Now,
=> AE = AB - BE
=> AE = 15 - 10 . [ BE = CD ]
=> AE = 5m.
In ∆AEC,
➡ By Pythagoras theorem,
=> ( AC )² = ( AE )² + ( CE )².
=> (13)² = (5)² + (CE)².
=> 169 = 25 + (CE)².
=> (CE)² = 169 - 25.
=> CE = √144.
=> CE = 12m.
And, CE = BD.
So, BD = 12m. ( Distance between their feet ).
✔✔Hence, it is solved ✅✅.
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