two poles 15 metre and 10 metre high stand upright on the ground.if the distance between their top is 13 metre,find the horizontal distance between the poles
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Let the poles be AB and CD with AB>CD. If A perpendicular from CD joins AB at E, measurement of AE will be 5m and BE will be 10 m.
Consider tri AEC right angled at E, here we have AE= 5m, AC = 13m (given).
We have to find EC.
∵ tri AEC is a right triangle, we can apply Pythagoras Theorem.
We get:
AC² = EC² + AE²
⇒AC² - AE² = EC²
⇒13² - 5² = EC²
⇒169 - 25 = EC²
⇒144 = EC²
⇒EC = √144
⇒EC = 12
∴ DISTANCE BETWEEN THE TWO POLES IS 12m.
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