two poles 15m and 30m highare standing straight on the ground. if their feet are 36m feet apart, find the distance between their tops
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Let AB be pole of height 15m
and DC be pole of height 30m
In rt triangle DEB , angleE=90°
By Pythagoras theorem
![{36}^{2} + {15}^{2} = {bd}^{2} {36}^{2} + {15}^{2} = {bd}^{2}](https://tex.z-dn.net/?f=+%7B36%7D%5E%7B2%7D++%2B++%7B15%7D%5E%7B2%7D++%3D++%7Bbd%7D%5E%7B2%7D+)
ie
BD=39m
Thus the distance between their tops is 39m
and DC be pole of height 30m
In rt triangle DEB , angleE=90°
By Pythagoras theorem
ie
BD=39m
Thus the distance between their tops is 39m
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