two poles AB and PQ are standing opposite each other on either side of the road 200m wide from a point R between them on the road angle of elevation of the top of the pole AB and PQ 45 degree and 40 degree respectively if height of ab = 80m find the height of pq correct to the nearest metre
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Step-by-step explanation:
Tan 45= height of AB/BR
1 = 80/BR
BR = 80
Now,
Tan 40 = Height of PQ/200-80
O.8391= PQ/120
PQ =0.8391×120
PQ = 100.692
PQ ~~= 100.7m
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