Two poles are 'a' metres apart and the height of one is double the other. if from the midpoint of the line joining their bases an observer finds the angles elevation of their tops as 30 and 60, find the height of the smaller poletwo poles are 'a' metres apart and the height of one is double the other. if from the midpoint of the line joining their bases an observer finds the angles elevation of their tops as 30 and 60, find the height of the smaller poletwo poles are 'a' metres apart and the height of one is double the other. if from the midpoint of the line joining their bases an observer finds the angles elevation of their tops as 30 and 60, find the height of the smaller poletwo poles are 'a' metres apart and the height of one is double the other. if from the midpoint of the line joining their bases an observer finds the angles elevation of their tops as 30 and 60, find the height of the smaller poletwo poles are 'a' metres apart and the height of one is double the other. if from the midpoint of the line joining their bases an observer finds the angles elevation of their tops as 30 and 60, find the height of the smaller poletwo poles are 'a' metres apart and the height of one is double the other. if from the midpoint of the line joining their bases an observer finds the angles elevation of their tops as 30 and 60, find the height of the smaller poletwo poles are 'a' metres apart and the height of one is double the other. if from the midpoint of the line joining their bases an observer finds the angles elevation of their tops as 30 and 60, find the height of the smaller pole
Ramcharan:
ya...even i got it like that.....but it cant be a wrong question..coz its from an all india xam paper
was writing that yesterday and if any question was wrong they wud hav told me...but no one did
they ? who?
teachers...who else!
okkkkkkkkkkkkkkkk
yet im posting it
r u there?
ok
is it last year
no prajwal. this is there in this year sample paper
Answers
Answered by
2
Let the AB (short pole) = a m
⇒ MJ (Tall pole) = 2a m
Midpoint of of BJ be E
⇒Let BE=JE=x m
⇒ angle AEB =30°
⇒ angle MEJ = 60°
In triangle ABE
Tan 30° = AB/BE
1/ √3 = a/x [By cross multiplication]
⇒x=a√3 ----------------------1
In triangle MJE
Tan 60° = MJ/JE
√3 = 2a/x
x√3 = 2a [From 1]
a√3(√3) = 2a
3a - 2a =0
a=0
∴ Height of the short pole is 0 m.
Thank You......!!!!!!!!!
Mark as brainliest if helpful...
Yours, Jahnavi.
⇒ MJ (Tall pole) = 2a m
Midpoint of of BJ be E
⇒Let BE=JE=x m
⇒ angle AEB =30°
⇒ angle MEJ = 60°
In triangle ABE
Tan 30° = AB/BE
1/ √3 = a/x [By cross multiplication]
⇒x=a√3 ----------------------1
In triangle MJE
Tan 60° = MJ/JE
√3 = 2a/x
x√3 = 2a [From 1]
a√3(√3) = 2a
3a - 2a =0
a=0
∴ Height of the short pole is 0 m.
Thank You......!!!!!!!!!
Mark as brainliest if helpful...
Yours, Jahnavi.
Similar questions