Two poles of 8m and 14m stand upright on a plane ground. If the distance between their tops is 10m.
Find the distance between their feet
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Step-by-step explanation:
Let AB and CD are the poles of heights 15m and 10m such thatAC is 13m.
Now,
CE=BD=10m
CD=BE=10m
∴AE=AB−BE=15−10=5m
Now, in triangle AEC
⇒(13)
2
=5
2
+(EC)
2
⇒(EC)
2
=169−25
⇒EC=
144
⇒EC=12
∴BD=12m
Therefore 12m is the distance between the fett of the poles.
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