Two poles of height 100 m and 111 m stand vertically upright on the surface
of the ground. If the distance between their feet is 60 m, find the distance between
their tops?
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Solution:-
The distance between their feet = 60 m
Height of first pole = 100 m and,
Height of second pole = 111 m
AC = DB - AE
AC = 111 m - 100 m
AC = 11 m
Now, In ΔABC
By Pythagoras theorem
AB² = AC² + bc²
AB² = 11² + 60²
AB² = 121 + 3600
AB = √3721
AB = 61 m
∴ The distance between their tops of the poles = 61 m.
Some Important Terms:-
- To find any side of Right-angled triangle always use Pythagoras theorem.
- Pythagoras Theorem was Discovered and Proved by Babylonian mathematician Pythagoras 1000 years ago.
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