Math, asked by DCRUDRA, 3 months ago

Two poles of height 100 m and 111 m stand vertically upright on the surface

of the ground. If the distance between their feet is 60 m, find the distance between

their tops?​

Answers

Answered by ridajunaid
17

Answer:

Step-by-step explanation:

Here is your answer

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DCRUDRA: THNX BRO
Answered by AadityaSingh01
8

Solution:-

The distance between their feet = 60 m

Height of first pole = 100 m        and,

Height of second pole = 111 m

AC = DB - AE

AC = 111 m - 100 m

AC = 11 m

Now, In ΔABC

By Pythagoras theorem

AB² = AC² + bc²

AB² = 11² + 60²

AB² = 121 + 3600

AB = √3721

AB = 61 m

The distance between their tops of the poles = 61 m.

Some Important Terms:-

  • To find any side of Right-angled triangle always use Pythagoras theorem.

  • Pythagoras Theorem was Discovered and Proved by Babylonian mathematician Pythagoras 1000 years ago.
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