Question

two poles of height 4m and 9m stand on a plane ground.if the distance between the feet of the poles is 12mt,find the distance between their tops​

Answer 1

GIVEN :-

• Two poles of height 4 m and 9 m stand on a plane ground.
• Distance between the feet of the poles is 12 m.

TO FIND :-

• The distance between their tops , DE.

CONSTRUCTION :-

• Draw DC ⟂ BC.

SOLUTION :-

As we know that,

» AB = DC = 12 m.

» AD = BC = 4 m.

✮ Length of EC,

➳ EC = BE - BC

➳ EC = 9 m - 4 m.

➳ EC = 5 m.

✭ Now in ∆ ECD By Pythagoras theorem,

➠ (DE)² = (DC)² + (CE)²

➠ (DE)² = (12)² + (5)²

➠ (DE)² = 144 + 25

➠ (DE)² = 169

➠ DE = √169

➠ DE = 13 m.

Hence the distance between the top of the poles is 13 m.

Answer 2

$\huge \mathbb{\boxed{\red{Question\:}}}$

Two poles of height 4m and 9m stand on a plane ground.if the distance between the feet of the poles is 12mt,find the distance between their tops

$\huge \mathbb{\boxed{\red{Solution\:}}}$

We know that

AB = CD = 12m

AC = BD = 9m

CD = ?

We have,

Two poles A and B of height 4m and 9m, distance between the two poles is 12m,

one side, poles, 9 - 4 = 5m

By Pythagoras theorem.

h² = 5² + 12²

h = √25 + 144

h = √169

h = 13

$\mathbb{\boxed{\red{Verification \:}}}$

We have to find the hypothenuse ∆CDE.

13² = 5² + 12²

169 = 25 + 144

169 = 169