Two poles of height 6 meter and 11 meters stand on a ground plane . If the distance between their feet is 12 meters, find the distance between their tops
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Draw it's diagram first...
u will get one right angled triangle
and a rectangle...AB(6m) and CD(11)
let E be the point on CD of length 6m(AB)
SO, GIVEN...BD =12 M...SO in rectangle ABDE, BD=AE=12m...so
CE=11-6=5m(length of CE)
NOW by using pythogarous thm..we get ,
AC = √169=13 m...hope it's clear....and hope it helps
u will get one right angled triangle
and a rectangle...AB(6m) and CD(11)
let E be the point on CD of length 6m(AB)
SO, GIVEN...BD =12 M...SO in rectangle ABDE, BD=AE=12m...so
CE=11-6=5m(length of CE)
NOW by using pythogarous thm..we get ,
AC = √169=13 m...hope it's clear....and hope it helps
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