Two poles of height 6m and 11 m stand on a plane ground. If the distance between their feet is 12 m,find the distance between their tops.
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Answer:
Let AB be the pole of 11m.
Let CD be the pole of 6m.
Draw CE parallel to BD
CE = BD = 12m
Now,
In right Triangle AEC
ACsquare = AEsquare + CEsquare
ACsquare = (11-6)square + 12square
ACsquare = 5*5 + 12*12
ACsquare = 25 + 144
ACsquare = 169
AC = root169
AC = 13m
Hope it helps
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