Two poles of height 7 m and 14 m to stand on a plane if the distance between their feet is 24 m then the distance between their tops is
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Here's your answer..⤵⤵
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Let AB = 14 m
DC = EB = 7 m
BC = DE = 24 m
In ∆AED, angle AED = 90°
AE² + ED² = AD²
7² + 24² = AD²
AD² = 49 + 576
AD² = 625
AD = √625
AD = 25 m
Distance between their tops is 25m.
______________________________
Hope it helps
Thanks :)
Here's your answer..⤵⤵
____________________
Let AB = 14 m
DC = EB = 7 m
BC = DE = 24 m
In ∆AED, angle AED = 90°
AE² + ED² = AD²
7² + 24² = AD²
AD² = 49 + 576
AD² = 625
AD = √625
AD = 25 m
Distance between their tops is 25m.
______________________________
Hope it helps
Thanks :)
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Answer :-
Let AB = 14 m
DC = EB = 7 m
BC = DE = 24 m
In ∆AED, angle AED = 90°
AE² + ED² = AD²
7² + 24² = AD²
AD² = 49 + 576
AD² = 625
AD = √625
AD = 25 m
Distance between their tops is 25m.
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