Two poles of height 8m nd 13m stand on a plane ground. if the distance between their tips is 13m , find the distance between their feet.
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Answered by
4
Hey !!
Here is your answer... ⬇⬇
Let AC be pole with height 13m, DE be the pole with height 8m and AE be the distance between their top 13m.
BC = DE = 8m
BE = CD
AB = AC - BC
AB = 13 - 8
AB = 5m
In ∆ABE, angle ABE = 90°
AB^2 + BE^2 = AE^2
( 5 )^2 + BE^2 = ( 13 )^2
BE^2 = 169 - 25
BE =√144
BE = 12m
BE = CD = 12m
Distance between their foot is 12m.
HOPE IT HELPS...
THANKS ^-^
Here is your answer... ⬇⬇
Let AC be pole with height 13m, DE be the pole with height 8m and AE be the distance between their top 13m.
BC = DE = 8m
BE = CD
AB = AC - BC
AB = 13 - 8
AB = 5m
In ∆ABE, angle ABE = 90°
AB^2 + BE^2 = AE^2
( 5 )^2 + BE^2 = ( 13 )^2
BE^2 = 169 - 25
BE =√144
BE = 12m
BE = CD = 12m
Distance between their foot is 12m.
HOPE IT HELPS...
THANKS ^-^
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Answered by
3
heya!!
Apply Pythagoras theorem in this question.
According to which,
h² = p² + b²
for detailed solution, refer to given attachment please
Apply Pythagoras theorem in this question.
According to which,
h² = p² + b²
for detailed solution, refer to given attachment please
Attachments:
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