two poles of height a metre and b metre are p metre apart. prove that the height of the point of intersection of the lines joining the top of each pole to the foot of the opposite pole is giveb by ab /a+b metre
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height of the point of intersection = ab/(a + b)
Step-by-step explanation:
ΔCOL ≈ ΔCBA
h/a = x/(x + y)
ΔAOL ≈ ΔADC
h/b = y/(x + y)
adding both
h/a + h/b = x/(x + y) +y/(x + y)
=> (bh + ah)/ab = (x + y)/(x + y)
=> h(a + b)/ab = 1
=> h = ab/(a + b)
QED
Similar triangle concept is used
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