Question

Two poles of heights 6m and 11m stand on a plane ground. If the distance between the foot of the poles 12m.Find the distance between their tops

Answer 1

$\bf\huge\underline{Answer}$

Let the poles AB and CD are such that the distance between their feet AC = 12m.

Since, Height of pole-I, AB = 11m

Height of pole-II, CD = 6m

Therefore, BE = 11m - 6m = 5m

Let us join the tops of the poles D and B.

Now, in right ∆BED, using the Pythagoras theorem, we have

⠀ DB² = DE² + EB²

=>DB² = 12² + 5² = 144 + 25 = 169

=> DB = √169 = 13m

Thus, the required distance between the tops is 13m.