Question

Two poles of heights 7 m and 12 m
stand vertically upright on a plane
ground. If the distance between their
feet is 12 m, then the distance
between their tops is

Answer 1

Answer:

13 m

Step-by-step explanation:

use Pythagoras theorem

12^2+5^2=144+25=169

so distance between their tops=under root(169)=13 m

Answer 2

The distance between tops of two poles is 13m.

Step-by-step explanation:

We are given two poles having height 7m and 12m respectively. distance between their feet is 12 m.

We have to find the distance between their tops in this question.

• Formula used,

we use Pythagoras theorem to find the distance between tops of two poles.

$H^{2} =P^{2} +B^{2}$

$H=\sqrt{P^{2} +B^{2} }$

H is the hypotenuse , P is the perpendicular and B is Base of right angled triangle.

• Calculation for the distance between tops of two poles.

For finding distance between tops, we draw a parallel line to the line of distance between feet of poles as we can see in attached picture,

Now we get a right angled triangle having perpendicular(P) and base(B) is,

$P=12-7$

   $=5m$

$B=12m$

now we have to find the hypotenuse (H) of right angled triangle by using Pythagoras theorem formula,

$H=\sqrt{P^{2} +B^{2} }$

    $=\sqrt{(5)^{2} +(12)^{2} }$

    $=\sqrt{25+144}$

    $=\sqrt{169}$

    $=13m$

We get the answer as the distance between tops of two poles is 13m.