Question

Two poles of heights 8m and 12m stand on a plane ground. If the distance between their

feet is 3m, find the distanc​

Answer 1

$\large\bf\blue{Right Question:-}$

Two poles of heights 8m and 12m stand on a plane ground. If the distance between their

feet is 3m, find the distance between their top.

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$\large\bf\red{Given}$

height=8m and 12m

distance between their feet = 3m

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$\large\bf\green{Solution:-}$

(Look at the attachment for Diagram)

ABCD is a Rectangle...

hence,

AB = DC = 8m

AD = BC = 3m

therefore,

DE = EC - DC.

=12-8=>4m

By applying Pythagoras theorem:-

${ae}^{2} = {ad}^{2} + {ed}^{2}$

${ae}^{2} = {3}^{2} + {4}^{2}$

${ae}^{2} = 25$

$ae = \sqrt{25} = 5$

5 m

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$\large\bf\</u><u>g</u><u>r</u><u>e</u><u>e</u><u>n</u><u>{</u><u>Answer</u><u>:</u><u>-</u><u>}$

Distance between their top= 5m

Answer 2

Answer:

Hope these attachments helps you