Question

Two poles of same strength attract each other with a force of magnitude F when placed at two corners of an equilateral triangle. If a north pole of same strength is placed at the third vertex, it experiences a force of magnitude equal to

Answer 1

Answer:

the resultant force on third corner is equal to F

Explanation:

As we know that two poles of same strength attract each other with force F

so here two poles must be of opposite nature

Now If north pole is placed at third corner of the triangle then one of the corner will apply attraction force on it while the other corner will apply repulsion force on it

So here we have two forces of same magnitude F will act on third corner which are inclined at 120 degree to each other

So the resultant of these two forces is given as

$F_{net} = \sqrt{F^2 + F^2 + 2(F)(F)cos120}$

$F_{net} = \sqrt{F^2 + F^2 - F^2}$

$F_{net} = F$

So the resultant force on third corner is equal to F

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Topic : Resultant Force

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