Question

Two positive ions and one negative ion are fixed at the vertices of an equilateral triangle. Where can a fourth ion be placed so that the force on it will be zero? Is there more than one such place?
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Answer 1

Answer:

The fourth ion should be placed at the centroid of the triangle.

Explanation:

The repulsive force applied by each positive ion on it will be balanced by the force of attraction applied by the negative ion so, the net force on it will be zero.