Question

two positive numbers differ by 3 and their product is 54 find the number

Answer 1

let the numbers be x and y

x-y= 3 (equation 1)

x=3+y

xy= 54 (eq 2)

sub x into eq 2

y(3+y)= 54

y^2 +3y -54 =0

therefore, y= 9 or -6 (however, disregard the -6 as the question says a positive number)

sub y=9 into one of the equations and get x = 6

therefore, y=9, x=6

Answer 2

Hello!

Let x and y are the two numbers .

According to the question :

• x - y = 3 ---(i)

• xy = 54
x + y =  √ (x-y)² + 4xy = √9 + 216  = √225 = 15

x + y =  15 ----(ii)

Solving (i) and (ii)

x = 9

y = 6

Hence, The two numbers are 6 and 9.

Cheers!