Math, asked by karanthakurforce, 9 months ago

- Two positive numbers x and y are such that
x > y. If the difference of these numbers is 5
and their product is 24, find :
(i) sum of these numbers.
(ii) difference of their cubes.
(iii) sum of their cubes.​

Answers

Answered by 217him217
2

Answer:

11

37

91

Step-by-step explanation:

8>3

x=8 y=3

x-y = 8-3 = 5

x+y = 8+3 =11

x³ - y³= 8³ - 3³ = 64-27 = 37

x³ + y³ = 64+27 = 91

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