Two prallel side of a trapezium are 58cm and 42cm. the other two side are of equal length which is 17cm. Find the area of trapezium
Answers
✬ Area = 750 cm² ✬
Step-by-step explanation:
Given:
- Measure of two parallel sides of trapezium are 58 cm and 42 cm.
- Measure of other two side of trapezium is 17 cm.
To Find:
- What is the area of trapezium ?
Solution: Let ABCD be a trapezium where
- AB || CD
- AB = 58 cm , CD = 42 cm
- AD = BC = 17 cm
Let us draw a perpendicular DE and CF from the vertex D and C onto the opposite side AB shown in the figure therefore,
- DC = EF = 42 cm
- { AE & FB are equal }
➟ AB = 58 cm
➟ AB = AE + EF + FB
➟ 58 = 2AE + EF
➟ 58 = 2AE + 42
➟ 58 – 42 = 2AE
➟ 16/2 = AE
➟ 8 cm = AE
Now in right angled triangle AED, by using Pythagoras Theorem
➙ AD² = DE² + AE²
➙ 17² = DE² + 8²
➙ 289 = DE² + 64
➙ 289 – 64 = DE²
➙ 225 = DE²
➙ √225 = DE
➙ 15 cm = DE
Here DE is the height of trapezium ABCD, As we know that
★ Ar. of ABCD = 1/2(Sum of || sides)(Height) ★
1/2(AB + DC)(DE)
1/2(58 + 42)(15)
1/2(100)(15)
100/2(15)
50 15
750 cm²
Hence, area of trapezium is 750 cm².
Two prallel side of a trapezium are 58cm and 42cm. the other two side are of equal length which is 17cm. Find the area of trapezium.
- Parallel sides = 42cm and 58cm
- Non-parallel sides = 17cm
- Area of trapezium
Draw AB || DE and DF ⊥ BC.
Therefore, AD || BC
and AB||DE (by Cons.)
Therefore ABED is a parallelogram.
AD = 42cm (opp. Sides of ||gm are equal)
EC = 58cm - 42cm = 16cm
EF = FC = 16/ 2 = 8cm
In △CDF
Using Pythagorous Theorm
➨Area of Trapezium = 1/2×Sum of || sides× h
➨Area of Trapezium = 1/2 ×( 42cm+ 58cm)× 15
➨Area of Trapezium = 1/2 × 100 cm × 15
➨Area of Trapezium = 750cm^2