two projectile A & B are projected with same initial velocity. The direction of A makes an angle pie/4 with the horizontal and find the angle of projectile B with horizontal when range of A will be doubled that of B
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0
Answer:
pi/12
Explanation:
Ra = v2 sin pi/2 /g
Rb = v2 sin 2x /g
Ra = 2 Rb
=> v2 sin pi/2 /g =2 * v2 sin 2x /g
=> sin pi/2 =2 sin 2x
=> sin 2x = 1/2
=> 2x = pi/6
=> x = pi/12
Answered by
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Answer:
Explanation
ANSWER
From formual of Range-
R=
g
u
2
sin2x
R
2
R
1
=(
u
2
u
1
)
2
×(
sin2x
2
sin2x
1
)
sin2x
2
=sin2x
1
×(
u
2
u
1
)
2
……[R
1
=R
2
]
sin2x
2
=sin30×(
v
2
v
)
2
sin2x
2
=1
sin2x
2
=sin90
x
2
=
2
90
x
2
=45
Angle of projection of B is 45
0
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