Physics, asked by sri2869, 10 months ago

two projectiles from the same point at angles 60 and 30 with the horizantal attain the same height the ratio of their initial velocities is​

Answers

Answered by akshaygandhirock
8

h1=h2

u1²sinΦ1=u2²sin²θ2u1/u2= sin 30/sin60=1/2/√3/2

u1/u2=1/√3

your welcome

Answered by QueenFlorA
6

Hello mate..

Here Is Your Answer:

GIVEN:

θ(1) = 60 \\ θ(2) = 30 \\ h(1) = h(2)

 \pink{formula \: for \: finding \: max \: height \:   \frac{ {u}^{2}  {sin}^{2}  \alpha }{2g} }

As, H(1) = H(2)

 \huge\frac{ {u}^{2}  {sin}^{2}  \alpha }{2g}  = \frac{ {u}^{2}  {sin}^{2}  \alpha }{2g}

2g gets cancelled.

 {u(1)}^{2} \ {sin(60)}^{2}   = {u(2)}^{2} \ {sin(30)}^{2} \\  \frac{ {u(1)}^{2} }{ {u(2)}^{2} } =   \frac{{ \sin }^{2}30}{{ \sin }^{2}60} \\  \frac{1}{ \sqrt{3} }  = 1:  \sqrt{3}

HOPE THIS HELPS YOU..

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