Physics, asked by sri2869, 1 year ago

two projectiles from the same point at angles 60 and 30 with the horizantal attain the same height the ratio of their initial velocities is​

Answers

Answered by akshaygandhirock
8

h1=h2

u1²sinΦ1=u2²sin²θ2u1/u2= sin 30/sin60=1/2/√3/2

u1/u2=1/√3

your welcome

Answered by QueenFlorA
6

Hello mate..

Here Is Your Answer:

GIVEN:

θ(1) = 60 \\ θ(2) = 30 \\ h(1) = h(2)

 \pink{formula \: for \: finding \: max \: height \:   \frac{ {u}^{2}  {sin}^{2}  \alpha }{2g} }

As, H(1) = H(2)

 \huge\frac{ {u}^{2}  {sin}^{2}  \alpha }{2g}  = \frac{ {u}^{2}  {sin}^{2}  \alpha }{2g}

2g gets cancelled.

 {u(1)}^{2} \ {sin(60)}^{2}   = {u(2)}^{2} \ {sin(30)}^{2} \\  \frac{ {u(1)}^{2} }{ {u(2)}^{2} } =   \frac{{ \sin }^{2}30}{{ \sin }^{2}60} \\  \frac{1}{ \sqrt{3} }  = 1:  \sqrt{3}

HOPE THIS HELPS YOU..

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