two protons are 6.0 into 10 to the power minus 15 apart find the electrostatic potential energy
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hey mate
here is your answer
the electrosatic potential energy=kQq/r
when k is the Coulomb's constant.
Q and q are the charges
r is the distance
hence,
=(k*2*1.6*10^-19)/6.0*10^-15
=k*3.2*10^-19/6*10^-15
=k*3.2*10^-19+15*1/6
=k*3.2*10^-4*1/6
=9*10^9*3.2*10^-4*1/6
=1.5*10^9*3.2*10^-4
=1.632*10^6 j (answer)
if r=6*10^-19 m
here is your answer
the electrosatic potential energy=kQq/r
when k is the Coulomb's constant.
Q and q are the charges
r is the distance
hence,
=(k*2*1.6*10^-19)/6.0*10^-15
=k*3.2*10^-19/6*10^-15
=k*3.2*10^-19+15*1/6
=k*3.2*10^-4*1/6
=9*10^9*3.2*10^-4*1/6
=1.5*10^9*3.2*10^-4
=1.632*10^6 j (answer)
if r=6*10^-19 m
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