Question

Two protons are separated by a distance 1A°, if they are released, what is the kinetic energy of each proton when at infinite separation?

Answer 1

Total kinetic energy of both proton=total initial potential energyq1=1.6×10−19 Cq2=1.6×10−19 Cr=1×10−10 mTotal kinetic energy of both proton=14πε0×q1q2rTotal kinetic energy of both proton=9×109×1.6×10−19×1.6×10−191×10−10Total kinetic energy of both proton=23.04×10−19 JThis kinetic energy is equally shared by both proton.So, kinetic energy of each proton=23.04×10−192=11.52×10−19 J