Two psitive number x and y are inversely proportional .If x increase by20% ,then presantge decrease in y is ?
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according to question,
in the case of inversely proportional product of the numbers must always be constant.
let the value of both x and y be 20.
then,
product = constant
xy = constant
20×20 = constant
400 = constant
if x is increased 20 % then new value of x will be = 20 + 20 % 20
= 20 + 4 = 24
x = 24
product = 400
xy = 400
24 × y = 400
y = 400/24
y = 50 / 3
decrease in y
= ( x - y / x ) × 100
={ ( 20 - 50 / 3 ) / 20 } × 100
=( 10/ 3×20 ) × 100
= 1000 / 60
= 100 / 6 = 50 / 3 = 16 whole 2/ 3
= 16.66 %
therefore , y will be decreased by 16.66%.
in the case of inversely proportional product of the numbers must always be constant.
let the value of both x and y be 20.
then,
product = constant
xy = constant
20×20 = constant
400 = constant
if x is increased 20 % then new value of x will be = 20 + 20 % 20
= 20 + 4 = 24
x = 24
product = 400
xy = 400
24 × y = 400
y = 400/24
y = 50 / 3
decrease in y
= ( x - y / x ) × 100
={ ( 20 - 50 / 3 ) / 20 } × 100
=( 10/ 3×20 ) × 100
= 1000 / 60
= 100 / 6 = 50 / 3 = 16 whole 2/ 3
= 16.66 %
therefore , y will be decreased by 16.66%.
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