Two pulleys of masses 12 kg and 8 kg are connected by a fine string hanging over a fixed pulley. Over the 8 kg pulley is hung a fine string with masses 4 kg and M. Over the 12 kg pulley is hung another fine string with masses 3 kg and 6 kg.Calculate M so that the string over the fixed pulley remains stationary
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For the heavier object, using F = ma,
8g - T = 8a 1
For the lighter object, using F = ma,
T - 2g = 2a 2
1 + 2 => 6g = 10a
a = 6ms-2
For the system,
u = 0, a = 6, t = 4
s = 0 x 4 + 1/2 x 6 x 16
s = 48 m
v = 0 + 6 x 4
v = 24 ms-1
8g - T = 8a 1
For the lighter object, using F = ma,
T - 2g = 2a 2
1 + 2 => 6g = 10a
a = 6ms-2
For the system,
u = 0, a = 6, t = 4
s = 0 x 4 + 1/2 x 6 x 16
s = 48 m
v = 0 + 6 x 4
v = 24 ms-1
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