Question

Two rectangular house lots are for sale. Although the width is different for the two lots, they are both 110 feet long. The area of lot A is 4,950 feet and the area of lot B is 7,920 feet. What is the ratio of the width of lot A to the width of lot B? A. 5:8

Answer 1

Answer:

5:8

Step-by-step explanation:

4950/110=45

7920/110=72

45:72⇒45/9:72/9=5:8

Answer 2

Solution!

The length of two rectangular house lots is given along with the areas of those house lots. We have to find the ratio of the width of lot A to the width of lot B and to do so, we have to calculate the widths of the rectangular lots.

Length of both the lots = 110 feet

Area of lot A = 4950 sq feet

Area of lot B = 7920 sq feet

We can find the widths one by one. Let's calculate the width of lot A and then lot B.

Area of lot A = Length × Width of lot A

4950 = 110 × Width of lot B

Width of lot B = 4950 ÷ 110

Width of lot A = 45 feet

Area of lot B = Length × Width of lot B

7920 = 110 × Width of lot B

Width of lot B = 7920 ÷ 110

Width of lot B = 72 feet

Ratio = Width of lot A ÷ Width of lot B

Ratio = 45 ÷ 72

Ratio = 5/8

Ratio = 5:8

Hence, the ratio of the width of lot A to the width of lot B equals 5:8.