Question

Two resistance of 3 ohm and 6 ohm are connected in parallel. This combination is connected in series with a resistance of 8 ohm. If supply voltage is 100 v , determine :

Answer 1

1/R'= 1/3 ohm+ 1/6 ohm

1/R'= 3/6 ohm= 1/2 ohm

R'=2ohm

Now series.....

R''= (2+8) ohm

R''= 10 ohm

So, total equivalent resistance is 10 ohm.

According to Ohm's law,

V=I R

By rearranging, we get,

I= V/R

I= (100/10)A

I= 10A

Hence the total current flowing through the circuit is 10 Ampere.

HOPE THIS HELPS!

Answer 2

if 2 resistance is connected in paralIel
then,
Rp. =. 1/r1 + 1/r2
= 1/3 + 1/6
= 2+1/6
=. 3/6 became
=. 1/2ohm

Rp=2ohm

Rs= 8ohm

I=V×R
I = 100/10 =10A