Question

two resistance of 4 ohm and 8ohm are connected in parallel. what would be the combined resistance of the system

Answer 1

Answer:8/3 ohm

Explanation:

1/r(eq) = 1/r1 + 1/r2 ......

=>1/req = 1/4 + 1/8

LCM = 8

= (2+1)/8

=3/8

=> req = 8/3

Answer 2

The combined resistance of the system in parallel is 2.67 ohms.

Explanation:

It is given that,

Resistance 1, $R_1=4\ \Omega$

Resistance 2, $R_1=8\ \Omega$

It is mentioned that the two resistors are connected in parallel. In parallel combination of resistors, the equivalent resistance is given by the below formula as :

$\dfrac{1}{R_{eq}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

$\dfrac{1}{R_{eq}}=\dfrac{1}{4}+\dfrac{1}{8}$

$R_{eq}=2.67\ \Omega$

So, the combined resistance of the system in parallel is 2.67 ohms. Hence, this is the required solution.

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