Two resistance R1 (100 ± 3)Ω and R2 (150 ± 2) are connected in series , what is their equivalent resistance ?
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Two resistances R1=(100±3) lamuda R2=(150±2)lamuda,are connected in series. What is their equivalent resistance?
Solution
R1 = 100 ± 3Ω
R2 = 150 ± 2Ω
To find : Equivalent resistance
Let equivalent resistance be R, = ?
R = R1 + R2
= (100 ± 3) + (150 ± 2)
= (100 + 150) (3 + 2)
= (3 + 2) + (250)
R = (250 ± 5)Ω
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