Question

Two resistances of R1= 5 omaga and R2 = 10 omaga are connected to a 24V battery. Find a] the effective resistance [b] the current in the section AB [c] theCurrent through each resistance,
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Answer 1

There are two possibilities in which the resistors can be connected

1) Series

Net resistance

Rs =R 1+ R 2

Rs =15 ohm

Voltage of the battery =25V

Current flowing through the combination

I = V /Rs

I =25/15

I=1.6 ohm

we know that in series combination the current flowing through both the resistors is the same

I 1= I 2 = 1.6 A

2) Parallel

R 1 and R2 are connected in parallel

Net resistance

Rp =R 1×R 2/ R 1+ R 2

Rp=25×15/40

Rp=9.37 ohms

Voltage of the battery=25 V

Current flowing through the parallel combination

I = V /Rp =25/9.37

I=2.66A

In parallel combination we know that the voltage across both the resistors is the same

I 1 = V /R 1 = 25/25 =1 A

I 2 = V / R 2 =25 /15 =1.66 A