Two resistances R1=100+-3ome and R2 =200+-4ome are connected in series. Then what isthe equivalent resistances?
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Answered by
6
R₁ = (100 ± 3) Ω
R₂ = (200 ± 4) Ω
In series arrangement equivalent resistance is
R = R₁ + R₂
= (100 ± 3) Ω + (200 ± 4) Ω
= (300 ± 7) Ω
∴ Equivalent Resistance is (300 ± 7) Ω
R₂ = (200 ± 4) Ω
In series arrangement equivalent resistance is
R = R₁ + R₂
= (100 ± 3) Ω + (200 ± 4) Ω
= (300 ± 7) Ω
∴ Equivalent Resistance is (300 ± 7) Ω
Answered by
3
HEY!!
R1 = 100±3 ohm
R2 = 200±4 ohm
As they are connected in series,
R = R1 + R2R = 100 + 200 = 300 ohm
error:
∆R = ∆R1 + ∆R2 = 3+4 = 7 ohmR = 300±7 ohm
R1 = 100±3 ohm
R2 = 200±4 ohm
As they are connected in series,
R = R1 + R2R = 100 + 200 = 300 ohm
error:
∆R = ∆R1 + ∆R2 = 3+4 = 7 ohmR = 300±7 ohm
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