two resistances R1 and R2 (R1 <R2) are connected in parallel their equivalent resistance R is
Answers
Answered by
2
Answer:
Two resistors, R
1
andR
2
are connected in parallel.
We know,
R
e
1
=
R
1
1
+
R
2
1
Then R
e
=
R
1
+R
2
R
1
R
2
=
50+100
50×100
=
150
5000
=
3
100
Now, Parallel Connection error:
=
(R
1
+R
2
)
2
R
1
2
(dB)+R
2
2
(dA)
=
150
2
50
2
(3)+100
2
(2)
=
150×150
7500+20000
=
9
11
Relative Error =
(100/3)
(11/9)
=0.03666
Answered by
6
Answer:
R2+R1/R1R2
Explanation:
let r be the equivalent resistence, therefore
1/r=1/R1+1/R2
u will get the answer by solving it..
hope it will help u
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