Question

Two resisters are connected in series gives an
equivalent resistance of 10 ohm . When connected in
parallel, gives 2.4 ohm . Then the individual resistance
are :
(a) each of 5 ohm (6) 6 ohm and 4 ohm
- (c) 7 ohm and 4 ohm (d)8 ohm and 2 ohm​

Answer 1

Answer:

given that when connected in series equivalent resistance is 10 ohm

x1 +x2 = 10

when Connected in parallel equivalent resistance is 2.4 ohm = 24 /10

1/x1 + 1/ x2 = 10 /24

x1 + x2 / x1.x2 =10/24

10/ x1.x2 =10/24

x1.x2 = 24

the individual resistance are 6, 4

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