Question

two resistor of values 30 and 60 are connected in a parallel. calculate their effective resistance​

Answer 1

Answer:

1/R =1/r1 + 1/r2 +….. + 1/rn

Where r1, r2 are the resistors which are connected in parallel,

So according to above formula

We have,

Req=30*60/90 = 20.

Answer 2

Answer:

$\frac{1}{30} + \frac{1}{60}$

$\frac{2 + 1}{60}$

$\frac{3}{60}$

$\frac{1}{20}$

which is equal to

$\frac{1}{r}$

so r=20

hence effective resistance =20

Hope u understand. thank uhh