Two resistor with resistance 5 ohms and 10 ohms are to be connected to a battery of 6 V so as to obtain: 1) minimum current 2) maximum current a) How will you connect the resistance in each case. b) calculate the strength of the total current in the two cases.
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Given: Two resistors with resistances R1=5ohm and R2=10ohm, V=6volt
(a) For minimum current these two should be connected in series. For maximum current these two should be connected in parallel.
(b)In series, Total resistance = 5+10 = 15ohms Therefore total current drawn = V/R = 6/15 = 0.4amps In parallel, Total resistance R is given as 1/R=1/R1+1/R2 1/R =1/5+1/10 1/R=3/10 R=10/3 ohm
Therefore total current drawn by the circuit = V/R = 6/(10/3) =1.8amps.
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