two resistors 3ohm and 6ohm are combined in parallel , if the combination is connected to a battery of emf 10V and negligible internal resistance , determine the current drawn from the battery ?
Answers
Answered by
0
Answer:
5
Explanation:
current is 5 A . V=IR is the formula.
Answered by
0
Answer:
Given:-
R1=30 ohm
R2= 60 ohm
then equivalent resistance( Req) =R1+R2
=30+60
; =90ohm
then
From ohms law
Current =voltage/resistance
i = v/R
=10/90
= 1/9 ampere
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