Question

Two resistors having resistance of 16 W and 14W are connected in series. If a potential difference of 18 V is applied across them, calculate the current flowing through the circuit and the potential difference across the end of each individual resistor.​

Answer 1

Explanation:

ANSWER

Given: A resistance of 3Ω is connected in series with another resistance of 5Ω. A potential difference of 6V is applied across the combination.

To find the current through the circuit and potential difference across the 3Ω resistance.

Solution:

as the resistance are connected in series

so R=R

1

+R

2

=3+5=8Ω

now according to Ohm's law,

R=IR

⟹I=

R

V

⟹I=

8

6

⟹I=0.75A

So, 0.75A of current flow through circuit.

Now , Potential Difference across the 3Ω resistance is

V

1

=IR

1

⟹V

1

=0.75×3

⟹V

1

=2.25V

Now the corresponding current will be,

I

1

=

R

1

V

1

⟹I

1

=

3

2.25

⟹I

1

=0.75A=I

and we know that the same current flow through each of the resistance in series.