Question

Two resistors of 10 Ω and 15 Ω are connected in series to a battery of 6 V. How can the values of current passing through them be compared?

Answer 1

Explanation:

total = 10+15

= 25

voltage = 6

then,

6/25

= 0.24 A

Answer 2

Answer:they are connected in series

Then,Req=R1+R2

Req=15+10=25Ω

And v=6v

From ohms law,

V=iR

I=6/25=0.24 amperes

In 15ohms resistor current flow is

I=6/15=0.4amperes

In 10ohms resistor current flow is

I=6/10=0.6amperes

Explanation:

Hope it helps you....